X^2-69x+540=0

Solution for X^2-69x+540=0 equation:

X^2-69X+540=0

a = 1; b = -69; c = +540;
Δ = b2-4ac
Δ = -692-4·1·540
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-69)-51}{2*1}=\frac{18}{2}
=9
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-69)+51}{2*1}=\frac{120}{2}
=60
$